2. We have to calculate the magnitude of the satellite acceleration. v = Orbital velocity of the satellite. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students. Draw a vertical line from the satellite perpendicular to the surface. Mass of Earth: 6*1024 kg, radius of Earth = 6400 km. The acceleration due to gravity of the satellite can be found from the formula: g = 9.078 m/s 2. I keep overthinking it, need help with math ? Me = Mass of the earth. Altitude of the satellite above the Earth’s surface is approximately 36 000 km. Therefore the critical velocity of the satellite orbiting very close to the earth’s surface. would paying people to NOT have children help to limit population growth? In this case, you add the distance from the center of the Earth to the surface of the Earth, 6.38 × 10 6 meters, to the satellite’s height above the Earth. To solve this problem we have to know some constant values. The height above the Earth surface is {eq}h = \dfrac{R}{2} {/eq}. A satellite’s latitude (ψ) is the latitude of the point directly beneath the satellite on Earth. However, many systems can also use the GLONASS satellite constellation to get more satellites visible, especially near the … 0.1 C.) 0.19 D.)0.019 I THINK IT IS B? https://physicsteacher.in/2017/10/28/kepler-third-law-equation-derivation Coverage And Orbits. A satellite of mass 1000 kg is supposed to orbit the earth at a height of 2000 km above the earth's surface. How will the U.K. royals respond to TV interview? I simply canNOT get the answer. A satellite is revolving in a circular orbit at a height h from the Earth's surface (radius of Earth R,h<
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